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Lesson 3 of 4 35 min

EV Charging and Energy

AC and DC charging, charger power, efficiency and the charging-time calculation, including why the real curve is not a straight line.

In this lesson
  • Distinguish AC charging from DC charging
  • Calculate ideal and efficiency-corrected charging time
  • Explain why charging power tapers and the estimate is approximate

AC charging uses the vehicle’s onboard charger to convert the supply to DC. DC charging bypasses the onboard charger and supplies DC directly to the battery, which is why it can deliver much higher power. In both cases the battery, the charger and the thermal system limit the power that can be accepted at any moment.

t = E ÷ (P × η)
Charging time estimate; E is energy added in kWh, P charger power in kW and η the charging efficiency as a fraction.
Worked example

Charging time estimate

Problem. A 60 kWh battery is charged from 0% to 100% with an 11 kW charger at an overall efficiency of 0.90. Estimate the time.

Solution. Ideal time = 60 ÷ 11 = 5.45 h. Corrected for efficiency: 5.45 ÷ 0.90 = 6.06 h, approximately 6.1 h.

Why the real curve tapers

A battery does not accept full power across the whole state-of-charge range. Charging power typically tapers as the battery fills and as temperature limits are reached. The straight-line estimate is therefore a lower bound on time for a full charge, not a prediction of the exact curve.

  • AC charging uses the onboard charger.
  • DC charging supplies DC directly to the battery.
  • Efficiency losses mean more energy is drawn than is stored.
  • Charging power tapers with state of charge and temperature.
  • Cable, connector and supply limits also cap the power.
Charging equipment, connector types and installation requirements are defined by local standards and the vehicle manufacturer. Do not infer a safe installation from a power calculation alone.
Key points.
  • AC charging goes through the onboard charger.
  • DC charging feeds the battery directly.
  • t = E/(P × η) estimates charging time.
  • Real charging tapers, so the estimate is approximate.
Practice

Worked example

Adding 30 kWh with a 7 kW charger at 0.90 efficiency takes 30 ÷ (7 × 0.90) = 4.76 h, approximately 4.8 h.

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