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DC Electricity Intermediate 9 min read Nov 2026

Series–Parallel Circuits

Most real circuits combine series and parallel sections. Learn how to reduce a network step by step, find branch currents and verify the result with Kirchhoff’s laws.

Definition

A series–parallel circuit contains both series and parallel connections. It is analysed by repeatedly replacing parallel groups with their equivalent resistance and adding series resistances, then working back to find branch voltages and currents.

Learning objectives

  • Identify series and parallel sections in a mixed circuit.
  • Reduce a series–parallel network to a single equivalent resistance.
  • Work back to find branch currents and voltages.
  • Verify results with Kirchhoff’s current and voltage laws.
Series–Parallel Circuits diagram A closed electrical circuit electrical principle schematic — not to scale
Series–Parallel Circuits — schematic illustration
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Progressive explanation

Start with the plain-language idea, then move into the engineering detail. Each level stands on its own, so you can stop at the depth you need.

Beginner The core idea
Real circuits are rarely purely series or purely parallel. A lamp and a resistor might be in series, and that combination might sit in parallel with another branch. To analyse such a circuit, simplify it in stages: first combine the parallel parts into one equivalent resistance, then add the series parts.

Once you have the total resistance, find the total current from the source voltage. Then work backwards through the circuit: the total current flows through the series elements, and it splits between parallel branches according to their resistances. Checking that the voltages and currents add up correctly confirms the result.
Intermediate How it behaves in a circuit
The reduction method relies on the fact that any two-terminal network of resistors has an equivalent resistance. Combine parallel groups with 1/R_p = Σ1/Rᵢ, then add series resistances: R_total = R_series + R_p. The source current is I = V/R_total. Series elements carry that current; the voltage across a parallel group is the remaining voltage after the series drops, and each branch current is V_group/R_branch.

Kirchhoff’s laws provide a check. The sum of the branch currents equals the current entering the parallel group, and the sum of all voltage drops around any loop equals the source voltage. A common mistake is to reduce the network correctly but then misapply the current when working back, so label each intermediate value clearly.
Advanced Limits, assumptions, engineering detail
Reduction works only for networks that can be decomposed into series and parallel combinations. Bridge networks and networks with cross connections cannot be reduced this way; they require mesh or nodal analysis, superposition, Thévenin/Norton equivalents or delta–star transformation. For linear networks, these methods are equivalent and the choice is a matter of convenience and numerical conditioning.

In real circuits, component tolerances and temperature coefficients mean the calculated division is nominal. Non-linear elements require iterative solution or load-line methods. At high frequency, parasitic capacitance and inductance make the simple resistive model inadequate, and the physical layout can create unintended coupling between branches. The reduction method remains a valuable first estimate and a sanity check for simulation results.

Formulas and variables

Parallel group
1 / R_p = 1 / R₁ + 1 / R₂ + …
R_p Equivalent resistance of the parallel group · Ω R₁, R₂ Branch resistances · Ω
20 Ω in parallel with 20 Ω gives 10 Ω.
Total resistance
R_total = R_series + R_p
R_total Total equivalent resistance · Ω R_series Series part · Ω R_p Parallel group equivalent · Ω
10 Ω in series with a 10 Ω parallel group gives 20 Ω.
Total current
I_total = V_source / R_total
I_total Source current · A V_source Source voltage · V R_total Total resistance · Ω
40 V across 20 Ω gives 2.0 A.

Units of measurement

QuantitySymbolUnit
Resistance R ohm (Ω)
Voltage V volt (V)
Current I ampere (A)
Power P watt (W)

Worked examples

Worked example

Series resistor with a parallel pair

Problem. A 10 Ω resistor is in series with a parallel pair of two 20 Ω resistors, across a 40 V source. Find the total current, the voltage across the parallel pair and the current in each 20 Ω branch.

Solution. Parallel pair: 20 || 20 = 10 Ω. R_total = 10 + 10 = 20 Ω. I_total = 40/20 = 2.0 A. Voltage across the series resistor = 2.0 × 10 = 20 V, so the parallel pair has 40 − 20 = 20 V. Each 20 Ω branch current = 20/20 = 1.0 A, and 1.0 + 1.0 = 2.0 A checks with KCL.

R_total = 20 Ω; I_total = 2.0 A; V_parallel = 20 V; branch currents = 1.0 A each.
Worked example

Unequal parallel branches

Problem. A 12 Ω resistor is in series with a parallel pair of 24 Ω and 8 Ω, across a 36 V source. Find the total current and the current in each parallel branch.

Solution. Parallel pair: 24 || 8 = (24 × 8)/(24 + 8) = 192/32 = 6.0 Ω. R_total = 12 + 6 = 18 Ω. I_total = 36/18 = 2.0 A. Voltage across 12 Ω = 2.0 × 12 = 24 V; parallel pair voltage = 36 − 24 = 12 V. Branch currents: 12/24 = 0.50 A and 12/8 = 1.5 A; sum = 2.0 A.

I_total = 2.0 A; branch currents = 0.50 A (24 Ω) and 1.5 A (8 Ω).

Practical applications

  • Automotive lighting and accessory circuits
  • Sensor bridges and signal conditioning
  • Industrial control and indicator circuits
  • Ladder networks and attenuators

Automotive applications

Vehicle circuits commonly combine series and parallel sections: a switch and fuse are in series with a lamp, while several lamps may be in parallel across the supply. A parallel branch that loses its ground can force current through another path, changing voltages in ways that simple series or parallel reasoning does not predict. Reducing the network section by section helps explain measured voltages and locate the fault.

Industrial applications

Industrial control panels often contain mixed networks of indicator lamps, relay coils and resistors. A resistor in series with an LED indicator, with several indicators in parallel, is a typical series–parallel arrangement. Understanding the reduction helps select resistor power ratings and diagnose why one indicator is dim or another does not light.

Measurement procedure

  1. Measure the source voltage and total current first to check the overall equivalent resistance.
  2. Measure the voltage across each parallel group; branch currents then follow from the branch resistances.
  3. De-energise and isolate a branch before measuring its resistance, because the rest of the network forms parallel paths.
  4. Compare measured branch currents with the calculated division and investigate significant discrepancies as possible faults.

Common mistakes

  • Reducing a parallel group but then applying the total current to a single branch.
  • Treating a bridge network as a simple series–parallel combination when it is not reducible that way.
  • Forgetting that the voltage across a parallel group is the source voltage minus the series drops.
  • Ignoring component tolerances when comparing calculated and measured values.

Safety considerations

  • Mixed networks can keep a branch live through an unexpected path; isolate and prove dead before work.
  • Check the power rating of every resistor in a divider, not only the total.
  • Do not assume a low-voltage circuit is harmless; batteries can deliver high fault currents through parallel paths.

Frequently asked questions

Can every circuit be reduced to a single resistance?
Every two-terminal linear resistive network has an equivalent resistance, but not every network can be reduced by simple series–parallel steps. Bridges need other methods.
How do I know where to start reducing?
Start with the parallel group that has no other connections between its branches, replace it with its equivalent, and repeat. Then add the remaining series elements.
Why do my calculated and measured values differ?
Component tolerance, temperature, meter loading, contact resistance and wiring resistance all cause differences. A large difference usually indicates a fault or a wrong assumption.
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