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Power & Energy Intermediate 10 min read Nov 2026

AC Power

AC power has three components: active, reactive and apparent. Learn the power triangle, instantaneous power and how to calculate each component correctly.

Definition

AC power is the rate of energy transfer in an alternating-current circuit. It is described by active power (real work), reactive power (energy exchanged with reactances) and apparent power (the product of RMS voltage and current).

Learning objectives

  • Distinguish active, reactive and apparent power
  • Calculate each component from voltage, current and phase angle
  • Apply the power triangle and check the result
  • Explain why reactive power oscillates but does no net work
  • Interpret power analyser readings correctly
AC Power diagram Power relationship triangle P V I P = V × I
AC Power — schematic illustration
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Progressive explanation

Start with the plain-language idea, then move into the engineering detail. Each level stands on its own, so you can stop at the depth you need.

Beginner The core idea
In a DC circuit, power is simply voltage times current. In AC, voltage and current may not peak together, so only part of the product does useful work. Active power, measured in watts, is the useful part. Apparent power, in volt-amperes, is the full product of RMS voltage and current. Reactive power, in var, is the part exchanged with magnetic or electric fields.

The three form a right triangle: apparent power is the hypotenuse, active power the horizontal side and reactive power the vertical side.
Intermediate How it behaves in a circuit
For sinusoidal quantities, P = Vrms × Irms × cos φ, Q = Vrms × Irms × sin φ and S = Vrms × Irms, with S² = P² + Q². The instantaneous power p(t) = v(t) × i(t) has an average equal to P and a double-frequency oscillation whose amplitude is S. Energy flows back to the source during part of each cycle when the load is reactive.

A purely resistive load has φ = 0, so P = S and Q = 0. A purely reactive load has φ = 90°, so P = 0 and Q = S: energy oscillates but no net work is done.
Advanced Limits, assumptions, engineering detail
Non-sinusoidal loads require separating fundamental and harmonic components. Active power includes harmonic power, while reactive-power definitions differ between standards; apparent power includes a distortion component. In three-phase systems, instantaneous power can be decomposed into constant and oscillating parts, and instantaneous p-q theory is used in active filters. Power-quality instruments may report different reactive values depending on the definition selected, so the standard used must be stated.

Formulas and variables

Active power
P = Vrms × Irms × cos φ
P Active power · W φ Phase angle · °
230 V × 10 A × cos 30° = 1992 W.
Reactive power
Q = Vrms × Irms × sin φ
Q Reactive power · var φ Phase angle · °
230 V × 10 A × sin 30° = 1150 var.
Apparent power
S = Vrms × Irms = √(P² + Q²)
S Apparent power · VA P Active power · W Q Reactive power · var
√(1992² + 1150²) ≈ 2300 VA.

Units of measurement

QuantitySymbolUnit
Active power P watt (W)
Reactive power Q volt-ampere reactive (var)
Apparent power S volt-ampere (VA)
Phase angle φ degree (°)

Worked examples

Worked example

Lagging load at 30°

Problem. A load draws 10 A at 230 V with the current lagging the voltage by 30°. Find P, Q and S.

Solution. S = 230 × 10 = 2300 VA. P = 2300 × cos 30° = 2300 × 0.866 = 1992 W. Q = 2300 × sin 30° = 2300 × 0.5 = 1150 var.

P = 1992 W, Q = 1150 var and S = 2300 VA.
Worked example

Purely capacitive load

Problem. A capacitor draws 5 A at 230 V with the current leading by 90°. Find the three power components.

Solution. S = 230 × 5 = 1150 VA. cos 90° = 0, so P = 0. sin 90° = 1, so Q = 1150 var.

P = 0 W, Q = 1150 var and S = 1150 VA: energy oscillates with no net work.
Worked example

Using the power triangle

Problem. A load has a power factor of 0.6 and draws 10 A at 230 V. Find P and Q.

Solution. S = 2300 VA. P = 2300 × 0.6 = 1380 W. Q = √(2300² − 1380²) = √(5 290 000 − 1 904 400).

P = 1380 W and Q = 1840 var.

Practical applications

  • Motor and transformer loading
  • Uninterruptible power supply sizing
  • Power-quality analysis
  • Electricity billing and demand charges
  • Filter and compensation design
  • Generator and inverter rating

Automotive applications

AC charging of electric vehicles, inverter outputs for auxiliaries and the alternator AC side all involve reactive behaviour. In DC traction systems the power is essentially active, but the AC side of chargers must meet power-factor and distortion requirements.

Industrial applications

Motors and transformers absorb reactive power to create their fields, so industrial supplies are sized in kVA as well as kW. Power-factor correction, harmonic filters and demand management all depend on separating the three power components.

Measurement procedure

  1. Use a power analyser to read P, Q, S and power factor together.
  2. Confirm the instrument uses true RMS and states which reactive-power definition it applies.
  3. Check the phase polarity of the current probe; a reversed probe gives a misleading sign.
  4. For distorted loads, record harmonics along with the total values.

Common mistakes

  • Adding active and reactive power arithmetically instead of as a right triangle.
  • Believing reactive power is useless; it is necessary to sustain magnetic and electric fields.
  • Using an averaging meter and misreading the RMS values.
  • Ignoring harmonic distortion when interpreting apparent power.

Safety considerations

  • Reactive components store energy; capacitors and inductors can remain hazardous after isolation.
  • High-power AC equipment presents arc-flash risk; use the correct procedures and PPE.
  • Discharge and verify before touching terminals of power-factor correction equipment.

Frequently asked questions

Does reactive power do useful work?
It does no net work, but it is required to establish magnetic fields in motors and transformers and electric fields in capacitors. Without it those devices could not operate.
Why do some tariffs charge for kVA rather than kW?
The supply equipment and cables must carry the total current, which depends on apparent power. Charging for kVA encourages customers to keep the power factor high.
What is the power triangle?
A right triangle with active power on the horizontal axis, reactive power on the vertical axis and apparent power as the hypotenuse. It encodes S² = P² + Q².
Can active power be negative?
Yes. A load that returns energy to the source, such as a regenerating drive or a discharging battery, has negative active power by the chosen sign convention.
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